What is the answer to 1/(4-x)+3/(6+x)=0 ?

The answer to 1/(4-x)+3/(6+x)=0 is x=9

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1/(4-x)+3/(6+x)=0

\frac{1}{4 - x} + \frac{3}{6 + x} = 0

x = 9

Solution steps

\frac{1}{4 - x} + \frac{3}{6 + x} = 0

Multiply by LCM

x + 6 + 3 (- x + 4) = 0

Move

6

to the right side

x + 3 (- x + 4) = - 6

Expand

3 (- x + 4) : - 3 x + 12

x - 3 x + 12 = - 6

Add similar elements:

x - 3 x = - 2 x

- 2 x + 12 = - 6

Move

12

to the right side

- 2 x = - 18

Divide both sides by

- 2

x = 9

Verify Solutions

Find undefined (singularity) points:

x = 4, x = - 6

Combine undefined points with solutions:

x = 9

\frac{2}{x} = \frac{5}{4 x} + 3

x^{- 2} - x^{- 1} - 20 = 0

\frac{x + 7}{x - 2} = \frac{2}{9}

\frac{2}{8} = \frac{n + 4}{n - 4}

x, F = - \frac{k}{x ^{2}}

What is the answer to 1/(4-x)+3/(6+x)=0 ?
The answer to 1/(4-x)+3/(6+x)=0 is x=9
Solve for x: 1/(4-x)+3/(6+x)=0
The solution is x=9