What is the answer to x^{-2}-x^{-1}-20=0 ?

The answer to x^{-2}-x^{-1}-20=0 is x=-1/4 ,x= 1/5

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x^{-2}-x^{-1}-20=0

x^{- 2} - x^{- 1} - 20 = 0

x = - \frac{1}{4}, x = \frac{1}{5}

Decimal Notation

x = - 0.25, x = 0.2

Solution steps

x^{- 2} - x^{- 1} - 20 = 0

Refine

\frac{1}{x ^{2}} - \frac{1}{x} - 20 = 0

Multiply by LCM

1 - x - 20 x^{2} = 0

Solve

1 - x - 20 x^{2} = 0 : x = - \frac{1}{4}, x = \frac{1}{5}

x = - \frac{1}{4}, x = \frac{1}{5}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - \frac{1}{4}, x = \frac{1}{5}

\frac{x + 7}{x - 2} = \frac{2}{9}

\frac{2}{8} = \frac{n + 4}{n - 4}

x, F = - \frac{k}{x ^{2}}

C, \frac{1 + TC}{C} = 1 + T

\frac{3 x + 5}{( x - 1 ) ( x ^{4} + 7 )} = 0

What is the answer to x^{-2}-x^{-1}-20=0 ?
The answer to x^{-2}-x^{-1}-20=0 is x=-1/4 ,x= 1/5
Solve for x: x^{-2}-x^{-1}-20=0
The solution is x=-1/4 ,x= 1/5