What are the solutions to the equation p^2+16p+18=-37 ?

The solutions to the equation p^2+16p+18=-37 are p=-5,p=-11

Find the zeros of p^2+16p+18=-37

The zeros of p^2+16p+18=-37 are p=-5,p=-11

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p^{2} + 16 p + 18 = - 37

p = - 5, p = - 11

Solution steps

p^{2} + 16 p + 18 = - 37

Move

37

to the left side

p^{2} + 16 p + 55 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 55}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 55 = 6

p_{1, 2} = \frac{- 16 \pm 6}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 16 + 6}{2 \cdot 1}, p_{2} = \frac{- 16 - 6}{2 \cdot 1}

p = \frac{- 16 + 6}{2 \cdot 1} : - 5

p = \frac{- 16 - 6}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

p = - 5, p = - 11

\frac{5 \cdot 180}{4}

8 n^{2} + 7 n - 15 = - 7

- 1 - 5

x^{2} + 4 (\frac{- 1 - x}{2})^{2} = 25

2 \leq 3 y + 11 \leq 14

What are the solutions to the equation p^2+16p+18=-37 ?
The solutions to the equation p^2+16p+18=-37 are p=-5,p=-11
Find the zeros of p^2+16p+18=-37
The zeros of p^2+16p+18=-37 are p=-5,p=-11