What is the answer to (x^4-1)/(x^3)=0 ?

The answer to (x^4-1)/(x^3)=0 is x=1,x=-1,x=i,x=-i

Solve for x: (x^4-1)/(x^3)=0

The solution is x=1,x=-1,x=i,x=-i

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\frac{x ^{4} - 1}{x ^{3}} = 0

x = 1, x = - 1, x = i, x = - i

Solution steps

\frac{x ^{4} - 1}{x ^{3}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{4} - 1 = 0

Solve

x^{4} - 1 = 0 : x = 1, x = - 1, x = i, x = - i

x = 1, x = - 1, x = i, x = - i

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 1, x = - 1, x = i, x = - i

\frac{8}{9} = \frac{12}{p}

\frac{5}{x + 3} + \frac{3 x}{x + 4} = 2

\frac{x - 3}{x + 4} = \frac{4}{5}

0.2 = \frac{x ^{2}}{65 - x}

x - 2 - \frac{x ^{2} - 3 x + 2}{x - 1} = 0

What is the answer to (x^4-1)/(x^3)=0 ?
The answer to (x^4-1)/(x^3)=0 is x=1,x=-1,x=i,x=-i
Solve for x: (x^4-1)/(x^3)=0
The solution is x=1,x=-1,x=i,x=-i