What are the solutions to the equation 6x^2+18x-60=-72 ?

The solutions to the equation 6x^2+18x-60=-72 are x=-1,x=-2

Find the zeros of 6x^2+18x-60=-72

The zeros of 6x^2+18x-60=-72 are x=-1,x=-2

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6 x^{2} + 18 x - 60 = - 72

x = - 1, x = - 2

Solution steps

6 x^{2} + 18 x - 60 = - 72

Move

72

to the left side

6 x^{2} + 18 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 6 \cdot 12}{2 \cdot 6}

1 8^{2} - 4 \cdot 6 \cdot 12 = 6

x_{1, 2} = \frac{- 18 \pm 6}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 18 + 6}{2 \cdot 6}, x_{2} = \frac{- 18 - 6}{2 \cdot 6}

x = \frac{- 18 + 6}{2 \cdot 6} : - 1

x = \frac{- 18 - 6}{2 \cdot 6} : - 2

The solutions to the quadratic equation are:

x = - 1, x = - 2

3 x - 15 \leq 10

x^{2} - 2 x + 2 = 0 - 576

(6 x^{2} y^{2})^{2}

6 x + 7 = 1

\frac{2 + 4 i}{1 + i}

What are the solutions to the equation 6x^2+18x-60=-72 ?
The solutions to the equation 6x^2+18x-60=-72 are x=-1,x=-2
Find the zeros of 6x^2+18x-60=-72
The zeros of 6x^2+18x-60=-72 are x=-1,x=-2