What are the solutions to the equation x^2-2x+2=0-576 ?

The solutions to the equation x^2-2x+2=0-576 are x=1+sqrt(577)i,x=1-sqrt(577)i

Find the zeros of x^2-2x+2=0-576

The zeros of x^2-2x+2=0-576 are x=1+sqrt(577)i,x=1-sqrt(577)i

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x^{2} - 2 x + 2 = 0 - 576

x = 1 + 577 i, x = 1 - 577 i

Solution steps

x^{2} - 2 x + 2 = 0 - 576

Refine

x^{2} - 2 x + 2 = - 576

Move

576

to the left side

x^{2} - 2 x + 578 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 578}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 578 : 2577 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 577 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 577 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 577 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 577 i}{2 \cdot 1} : 1 + 577 i

x = \frac{- ( - 2 ) - 2 577 i}{2 \cdot 1} : 1 - 577 i

The solutions to the quadratic equation are:

x = 1 + 577 i, x = 1 - 577 i

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What are the solutions to the equation x^2-2x+2=0-576 ?
The solutions to the equation x^2-2x+2=0-576 are x=1+sqrt(577)i,x=1-sqrt(577)i
Find the zeros of x^2-2x+2=0-576
The zeros of x^2-2x+2=0-576 are x=1+sqrt(577)i,x=1-sqrt(577)i