What is factor 49x^2-140xy+100y^2 ?

The solution to factor 49x^2-140xy+100y^2 is (7x-10y)^2

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factor 49x^2-140xy+100y^2

factor

49 x^{2} - 140 x y + 100 y^{2}

(7 x - 10 y)^{2}

Solution steps

49 x^{2} - 140 x y + 100 y^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

49 x^{2} = (7 x)^{2}

100 y^{2} = (10 y)^{2}

- 140 x y = - 2 \cdot 7 x \cdot 10 y

= (7 x)^{2} - 2 \cdot 7 x \cdot 10 y + (10 y)^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(7 x)^{2} - 2 \cdot 7 x \cdot 10 y + (10 y)^{2} = (7 x - 10 y)^{2}

= (7 x - 10 y)^{2}

\frac{x}{4} - 3 \geq - 5

x^{2} + 8 x \geq - 12

8 u^{2} + 8 u + 2 = 0

\frac{16 a ^{4} + 16 a}{a ^{2} + 1 - a}

(\frac{109}{50}) (\frac{157}{100})

What is factor 49x^2-140xy+100y^2 ?
The solution to factor 49x^2-140xy+100y^2 is (7x-10y)^2