What are the solutions to the equation 8u^2+8u+2=0 ?

The solutions to the equation 8u^2+8u+2=0 are u=-1/2

Find the zeros of 8u^2+8u+2=0

The zeros of 8u^2+8u+2=0 are u=-1/2

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8 u^{2} + 8 u + 2 = 0

u = - \frac{1}{2}

Solution steps

8 u^{2} + 8 u + 2 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 8 \cdot 2}{2 \cdot 8}

8^{2} - 4 \cdot 8 \cdot 2 = 0

u_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 8}

u = \frac{- 8}{2 \cdot 8}

\frac{- 8}{2 \cdot 8} = - \frac{1}{2}

u = - \frac{1}{2}

The solution to the quadratic equation is:

u = - \frac{1}{2}

\frac{16 a ^{4} + 16 a}{a ^{2} + 1 - a}

(\frac{109}{50}) (\frac{157}{100})

\frac{64}{4}

k^{4} + 8 k^{3} + 16 k^{2}

3 a^{2} + 16 a + 5

What are the solutions to the equation 8u^2+8u+2=0 ?
The solutions to the equation 8u^2+8u+2=0 are u=-1/2
Find the zeros of 8u^2+8u+2=0
The zeros of 8u^2+8u+2=0 are u=-1/2