What are the solutions to the equation u^2-5u+4=0 ?

The solutions to the equation u^2-5u+4=0 are u=4,u=1

Find the zeros of u^2-5u+4=0

The zeros of u^2-5u+4=0 are u=4,u=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

u^{2} - 5 u + 4 = 0

u = 4, u = 1

Solution steps

u^{2} - 5 u + 4 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

u_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, u_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

u = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

u = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

u = 4, u = 1

15 x^{4} - 17 x^{2} - 4

484

(x + 3) (3 x + 5) = 7

∣ 2 x - 7 ∣ - 3 > 2

4 x - x^{3}

What are the solutions to the equation u^2-5u+4=0 ?
The solutions to the equation u^2-5u+4=0 are u=4,u=1
Find the zeros of u^2-5u+4=0
The zeros of u^2-5u+4=0 are u=4,u=1