What are the solutions to the equation x^2+19x+60=0 ?

The solutions to the equation x^2+19x+60=0 are x=-4,x=-15

Find the zeros of x^2+19x+60=0

The zeros of x^2+19x+60=0 are x=-4,x=-15

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x^{2} + 19 x + 60 = 0

x = - 4, x = - 15

Solution steps

x^{2} + 19 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 1 \cdot 60}{2 \cdot 1}

1 9^{2} - 4 \cdot 1 \cdot 60 = 11

x_{1, 2} = \frac{- 19 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 19 + 11}{2 \cdot 1}, x_{2} = \frac{- 19 - 11}{2 \cdot 1}

x = \frac{- 19 + 11}{2 \cdot 1} : - 4

x = \frac{- 19 - 11}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = - 4, x = - 15

8 - 13 x + 5 x^{2}

11 \geq 8 + n

\frac{( \frac{2}{2} )}{( \frac{2}{2} )}

x^{2} (\frac{16 - x ^{2}}{4 x})

3 n^{2} - 42 n + 147

What are the solutions to the equation x^2+19x+60=0 ?
The solutions to the equation x^2+19x+60=0 are x=-4,x=-15
Find the zeros of x^2+19x+60=0
The zeros of x^2+19x+60=0 are x=-4,x=-15