What is the answer to 2x^{-2}-7x^{-1}-4=0 ?

The answer to 2x^{-2}-7x^{-1}-4=0 is x=-2,x= 1/4

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2x^{-2}-7x^{-1}-4=0

2 x^{- 2} - 7 x^{- 1} - 4 = 0

x = - 2, x = \frac{1}{4}

Solution steps

2 x^{- 2} - 7 x^{- 1} - 4 = 0

Refine

\frac{2}{x ^{2}} - \frac{7}{x} - 4 = 0

Multiply by LCM

2 - 7 x - 4 x^{2} = 0

Solve

2 - 7 x - 4 x^{2} = 0 : x = - 2, x = \frac{1}{4}

x = - 2, x = \frac{1}{4}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - 2, x = \frac{1}{4}

(\frac{15}{x + 3}) 7 - 9 x = 0

\frac{22}{x} = 0

x^{- 2} + 6 x^{- 1} + 2 = 0

\frac{1}{x} = \frac{2}{x + 6}

\frac{x}{2 + x} = \frac{1}{2}

What is the answer to 2x^{-2}-7x^{-1}-4=0 ?
The answer to 2x^{-2}-7x^{-1}-4=0 is x=-2,x= 1/4
Solve for x: 2x^{-2}-7x^{-1}-4=0
The solution is x=-2,x= 1/4