What is the answer to x^{-3}=27 ?

The answer to x^{-3}=27 is x= 1/3 ,x=-1/6+1/(2sqrt(3))i,x=-1/6-1/(2sqrt(3))i

Solve for x: x^{-3}=27

The solution is x= 1/3 ,x=-1/6+1/(2sqrt(3))i,x=-1/6-1/(2sqrt(3))i

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x^{- 3} = 27

x = \frac{1}{3}, x = - \frac{1}{6} + \frac{1}{2 3} i, x = - \frac{1}{6} - \frac{1}{2 3} i

Solution steps

x^{- 3} = 27

Refine

\frac{1}{x ^{3}} = 27

Multiply both sides by

x^{3}

1 = 27 x^{3}

Solve

1 = 27 x^{3} : x = \frac{1}{3}, x = - \frac{1}{6} + \frac{1}{2 3} i, x = - \frac{1}{6} - \frac{1}{2 3} i

x = \frac{1}{3}, x = - \frac{1}{6} + \frac{1}{2 3} i, x = - \frac{1}{6} - \frac{1}{2 3} i

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{1}{3}, x = - \frac{1}{6} + \frac{1}{2 3} i, x = - \frac{1}{6} - \frac{1}{2 3} i

x^{- n} = \frac{1}{x ^{n}}

t, P = \frac{w}{t}

- \frac{2 x}{( x ^{2} + 1 ) ^{2}} = 0

r, s = \frac{a}{1 - r}

\frac{x ^{2} - 9}{x ^{2} - 25} = x + 1

What is the answer to x^{-3}=27 ?
The answer to x^{-3}=27 is x= 1/3 ,x=-1/6+1/(2sqrt(3))i,x=-1/6-1/(2sqrt(3))i
Solve for x: x^{-3}=27
The solution is x= 1/3 ,x=-1/6+1/(2sqrt(3))i,x=-1/6-1/(2sqrt(3))i