What is the answer to solvefor 1/y =x+2,y ?

The answer to solvefor 1/y =x+2,y is y= 1/(x+2);\quad x\ne-2

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solvefor 1/y =x+2,y

solve for

\frac{1}{y} = x + 2, y

y = \frac{1}{x + 2}; x \neq = - 2

Solution steps

\frac{1}{y} = x + 2

Multiply both sides by

y

1 = x y + 2 y

Switch sides

x y + 2 y = 1

Factor

x y + 2 y : y (x + 2)

y (x + 2) = 1

Divide both sides by

x + 2; x \neq = - 2

y = \frac{1}{x + 2}; x \neq = - 2

\frac{5}{x + 2} = \frac{2}{x - 1}

p (1) = p^{- 1} (1)

\frac{14}{x} = 7

\frac{10}{14} = \frac{90}{5 c - 24}

\frac{7}{2 x} - \frac{1}{4} = - 2

What is the answer to solvefor 1/y =x+2,y ?
The answer to solvefor 1/y =x+2,y is y= 1/(x+2);\quad x\ne-2