What is the answer to 5-1/t = 4/(t^2) ?

The answer to 5-1/t = 4/(t^2) is t=1,t=-4/5

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5-1/t = 4/(t^2)

5 - \frac{1}{t} = \frac{4}{t ^{2}}

t = 1, t = - \frac{4}{5}

Decimal Notation

t = 1, t = - 0.8

Solution steps

5 - \frac{1}{t} = \frac{4}{t ^{2}}

Multiply by LCM

5 t^{2} - t = 4

Solve

5 t^{2} - t = 4 : t = 1, t = - \frac{4}{5}

t = 1, t = - \frac{4}{5}

Verify Solutions

Find undefined (singularity) points:

t = 0

Combine undefined points with solutions:

t = 1, t = - \frac{4}{5}

t, M - 5 N = \frac{f}{t}

\frac{1}{( x - 2 ) ^{2}} = 0

\frac{2 x + 3}{1 - x} = 4

8 x^{- 3} = 64

\frac{1}{x + 1} = 1 - \frac{x}{3}

What is the answer to 5-1/t = 4/(t^2) ?
The answer to 5-1/t = 4/(t^2) is t=1,t=-4/5
Solve for t: 5-1/t = 4/(t^2)
The solution is t=1,t=-4/5