What is the answer to (x^2+3x-a)/(x-2)=x+5 ?

The answer to (x^2+3x-a)/(x-2)=x+5 is x\ne 2;\quad 0=-10+a

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(x^2+3x-a)/(x-2)=x+5

\frac{x ^{2} + 3 x - a}{x - 2} = x + 5

x \neq = 2; 0 = - 10 + a

Solution steps

\frac{x ^{2} + 3 x - a}{x - 2} = x + 5

Multiply both sides by

x - 2

x^{2} + 3 x - a = x (x - 2) + 5 (x - 2)

Solve

x^{2} + 3 x - a = x (x - 2) + 5 (x - 2) :

True for all

x; 0 = - 10 + a

x \neq = 2

Verify Solutions

Find undefined (singularity) points:

x = 2

Since the equation is undefined for:

2

x \neq = 2; 0 = - 10 + a

\frac{x ^{2} + 1}{x} = 0

t, a = \frac{z - c}{t + 3}

\frac{a}{x} + \frac{b}{x} = c

\frac{14}{x} = \frac{10}{4}

\frac{( x + 3 ) !}{( x + 2 ) !} = 2

What is the answer to (x^2+3x-a)/(x-2)=x+5 ?
The answer to (x^2+3x-a)/(x-2)=x+5 is x\ne 2;\quad 0=-10+a