What is the answer to 1/((x-1)^2)+1=0 ?

The answer to 1/((x-1)^2)+1=0 is x=i+1,x=-i+1

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1/((x-1)^2)+1=0

\frac{1}{( x - 1 ) ^{2}} + 1 = 0

x = i + 1, x = - i + 1

Solution steps

\frac{1}{( x - 1 ) ^{2}} + 1 = 0

Multiply both sides by

(x - 1)^{2}

1 + (x - 1)^{2} = 0

Solve

1 + (x - 1)^{2} = 0 : x = i + 1, x = - i + 1

x = i + 1, x = - i + 1

8 + (\frac{1}{x} - 2) = 88

y, \frac{x}{y} = y - 6

\frac{1}{x + 1} = \frac{1}{x + 1}

5 = \frac{3}{x}

\frac{1}{x - 6} = \frac{x}{x + 8}

What is the answer to 1/((x-1)^2)+1=0 ?
The answer to 1/((x-1)^2)+1=0 is x=i+1,x=-i+1
Solve for x: 1/((x-1)^2)+1=0
The solution is x=i+1,x=-i+1