What is the answer to (x^2+2x)/((x+1)^2)=0 ?

The answer to (x^2+2x)/((x+1)^2)=0 is x=0,x=-2

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(x^2+2x)/((x+1)^2)=0

\frac{x ^{2} + 2 x}{( x + 1 ) ^{2}} = 0

x = 0, x = - 2

Solution steps

\frac{x ^{2} + 2 x}{( x + 1 ) ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} + 2 x = 0

Solve

x^{2} + 2 x = 0 : x = 0, x = - 2

x = 0, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = - 1

Combine undefined points with solutions:

x = 0, x = - 2

\frac{2}{x} = \frac{5}{12}

z + \frac{16}{z + 2} = 6

\frac{2}{5} = \frac{6}{x} - 2

\frac{x ^{2} - 4}{x + 4} = 0

\frac{2 x - 3}{x + 1} = \frac{2}{5}

What is the answer to (x^2+2x)/((x+1)^2)=0 ?
The answer to (x^2+2x)/((x+1)^2)=0 is x=0,x=-2
Solve for x: (x^2+2x)/((x+1)^2)=0
The solution is x=0,x=-2