What is the answer to ((x^4-1))/(x^3)=0 ?

The answer to ((x^4-1))/(x^3)=0 is x=1,x=-1,x=i,x=-i

Solve for x: ((x^4-1))/(x^3)=0

The solution is x=1,x=-1,x=i,x=-i

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\frac{( x ^{4} - 1 )}{x ^{3}} = 0

x = 1, x = - 1, x = i, x = - i

Solution steps

\frac{( x ^{4} - 1 )}{x ^{3}} = 0

Simplify

\frac{( x ^{4} - 1 )}{x ^{3}} : \frac{x ^{4} - 1}{x ^{3}}

\frac{x ^{4} - 1}{x ^{3}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{4} - 1 = 0

Solve

x^{4} - 1 = 0 : x = 1, x = - 1, x = i, x = - i

x = 1, x = - 1, x = i, x = - i

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 1, x = - 1, x = i, x = - i

2 x - 3 - \frac{x ^{2} + 1}{x - 2} = - 7

x, \frac{x - y}{2 x} = 3

(x) = \frac{x ^{2} - 5 x + 6}{x ^{2} - 4}

\frac{x ^{2}}{x ^{2} - 4} = 0

\frac{39}{x} = 13

What is the answer to ((x^4-1))/(x^3)=0 ?
The answer to ((x^4-1))/(x^3)=0 is x=1,x=-1,x=i,x=-i
Solve for x: ((x^4-1))/(x^3)=0
The solution is x=1,x=-1,x=i,x=-i