What is the answer to (x^2-9)/(3-x)=x+1 ?

The answer to (x^2-9)/(3-x)=x+1 is x=-2

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(x^2-9)/(3-x)=x+1

\frac{x ^{2} - 9}{3 - x} = x + 1

x = - 2

Solution steps

\frac{x ^{2} - 9}{3 - x} = x + 1

Simplify

\frac{x ^{2} - 9}{3 - x} : - x - 3

- x - 3 = x + 1

Move

3

to the right side

- x = x + 4

Move

x

to the left side

- 2 x = 4

Divide both sides by

- 2

x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 3

Combine undefined points with solutions:

x = - 2

y, x = \frac{y + 2}{y - 3}

\frac{1}{x} + 4 = 0

\frac{a}{x} = \frac{b}{c}

x, y = \frac{1}{x ^{2}}

0 = \frac{1}{x + 1}

What is the answer to (x^2-9)/(3-x)=x+1 ?
The answer to (x^2-9)/(3-x)=x+1 is x=-2
Solve for x: (x^2-9)/(3-x)=x+1
The solution is x=-2