What is the answer to (x^2+x-42)/(x-6)=x+7 ?

The answer to (x^2+x-42)/(x-6)=x+7 is x\ne 6

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(x^2+x-42)/(x-6)=x+7

\frac{x ^{2} + x - 42}{x - 6} = x + 7

x \neq = 6

Solution steps

\frac{x ^{2} + x - 42}{x - 6} = x + 7

Simplify

\frac{x ^{2} + x - 42}{x - 6} : x + 7

x + 7 = x + 7

Both sides are equal

True for all x

Verify Solutions

Find undefined (singularity) points:

x = 6

Since the equation is undefined for:

6

x \neq = 6

\frac{5}{x} = 10

\frac{2 x - 6}{x} = \frac{x - 4}{2}

\frac{7}{9} = \frac{4}{x}

\frac{x}{x - 2} - 2 = \frac{x}{x - 2}

\frac{1}{27} = b^{- 3}

What is the answer to (x^2+x-42)/(x-6)=x+7 ?
The answer to (x^2+x-42)/(x-6)=x+7 is x\ne 6
Solve for x: (x^2+x-42)/(x-6)=x+7
The solution is x\ne 6