What is the answer to 1/27 =b^{-3} ?

The answer to 1/27 =b^{-3} is b=3,b=-3/2+(3sqrt(3))/2 i,b=-3/2-(3sqrt(3))/2 i

Solve for b: 1/27 =b^{-3}

The solution is b=3,b=-3/2+(3sqrt(3))/2 i,b=-3/2-(3sqrt(3))/2 i

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\frac{1}{27} = b^{- 3}

b = 3, b = - \frac{3}{2} + \frac{3 3}{2} i, b = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

\frac{1}{27} = b^{- 3}

Refine

\frac{1}{27} = \frac{1}{b ^{3}}

Cross multiply

b^{3} = 27

Solve

b^{3} = 27 : b = 3, b = - \frac{3}{2} + \frac{3 3}{2} i, b = - \frac{3}{2} - \frac{3 3}{2} i

b = 3, b = - \frac{3}{2} + \frac{3 3}{2} i, b = - \frac{3}{2} - \frac{3 3}{2} i

Verify Solutions

Find undefined (singularity) points:

b = 0

Combine undefined points with solutions:

b = 3, b = - \frac{3}{2} + \frac{3 3}{2} i, b = - \frac{3}{2} - \frac{3 3}{2} i

\frac{5}{x} = \frac{15}{27}

\frac{3}{7 x} - \frac{5}{x} = 3

\frac{( x - 3 )}{x} = 0

d + n = \frac{a}{5 r}

\frac{3 x ^{2}}{x + 1} - 1 = 0

What is the answer to 1/27 =b^{-3} ?
The answer to 1/27 =b^{-3} is b=3,b=-3/2+(3sqrt(3))/2 i,b=-3/2-(3sqrt(3))/2 i
Solve for b: 1/27 =b^{-3}
The solution is b=3,b=-3/2+(3sqrt(3))/2 i,b=-3/2-(3sqrt(3))/2 i