What is the answer to (x^2-4x)/((x-2)^2)=0 ?

The answer to (x^2-4x)/((x-2)^2)=0 is x=4,x=0

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(x^2-4x)/((x-2)^2)=0

\frac{x ^{2} - 4 x}{( x - 2 ) ^{2}} = 0

x = 4, x = 0

Solution steps

\frac{x ^{2} - 4 x}{( x - 2 ) ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} - 4 x = 0

Solve

x^{2} - 4 x = 0 : x = 4, x = 0

x = 4, x = 0

Verify Solutions

Find undefined (singularity) points:

x = 2

Combine undefined points with solutions:

x = 4, x = 0

\frac{5}{x + 2} + \frac{3}{5 x + 3} = 0

\frac{- 2 x ^{2} + 5 x - 1}{2 x - 1} = 0

\frac{5 x}{x + 2} = \frac{3 x}{x + 1}

\frac{34}{x} = \frac{17}{2}

\frac{2 x}{x + 3} = 9 - \frac{6}{x + 3}

What is the answer to (x^2-4x)/((x-2)^2)=0 ?
The answer to (x^2-4x)/((x-2)^2)=0 is x=4,x=0
Solve for x: (x^2-4x)/((x-2)^2)=0
The solution is x=4,x=0