What is the answer to (2x^2-8)/(x^2)=0 ?

The answer to (2x^2-8)/(x^2)=0 is x=2,x=-2

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(2x^2-8)/(x^2)=0

\frac{2 x ^{2} - 8}{x ^{2}} = 0

x = 2, x = - 2

Solution steps

\frac{2 x ^{2} - 8}{x ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

2 x^{2} - 8 = 0

Solve

2 x^{2} - 8 = 0 : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 2, x = - 2

\frac{8}{x} = 1

2 - \frac{3}{x + 2} = \frac{4}{x - 2}

\frac{12}{x} + \frac{30}{x} = 1

\frac{x ^{2} - 1}{x ^{2} - 4} = 0

\frac{x + 2}{4} = \frac{2}{x}

What is the answer to (2x^2-8)/(x^2)=0 ?
The answer to (2x^2-8)/(x^2)=0 is x=2,x=-2
Solve for x: (2x^2-8)/(x^2)=0
The solution is x=2,x=-2