What is the answer to (x^2-1)/(x^2-4)=0 ?

The answer to (x^2-1)/(x^2-4)=0 is x=1,x=-1

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(x^2-1)/(x^2-4)=0

\frac{x ^{2} - 1}{x ^{2} - 4} = 0

x = 1, x = - 1

Solution steps

\frac{x ^{2} - 1}{x ^{2} - 4} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} - 1 = 0

Solve

x^{2} - 1 = 0 : x = 1, x = - 1

x = 1, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = 2, x = - 2

Combine undefined points with solutions:

x = 1, x = - 1

\frac{x + 2}{4} = \frac{2}{x}

\frac{2}{x} = \frac{5}{10}

x, \frac{2 ( y + 3 )}{x} = 2 w

\frac{15}{20} = \frac{3}{k}

R^{3} = 5 + \frac{H}{a}

What is the answer to (x^2-1)/(x^2-4)=0 ?
The answer to (x^2-1)/(x^2-4)=0 is x=1,x=-1
Solve for x: (x^2-1)/(x^2-4)=0
The solution is x=1,x=-1