What is factor n^2+4n-5 ?

The solution to factor n^2+4n-5 is (n-1)(n+5)

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factor n^2+4n-5

factor

n^{2} + 4 n - 5

(n - 1) (n + 5)

Solution steps

n^{2} + 4 n - 5

Break the expression into groups

= (n^{2} - n) + (5 n - 5)

Factor out

n

from

n^{2} - n : n (n - 1)

Factor out

5

from

5 n - 5 : 5 (n - 1)

= n (n - 1) + 5 (n - 1)

Factor out common term

n - 1

= (n - 1) (n + 5)

7 w^{5} - 35 w^{2}

x^{2} - x - 21 + x^{2} - 9 = 0

4 - x^{2} = 0

x, VV - 2 \cdot G \cdot R - K V \frac{V}{M} = x^{2} - K \cdot \frac{x ^{2}}{M} - 2 \cdot K V \frac{x}{M}

(\frac{81}{16})^{\frac{1}{4}}