What is the answer to 5+A=(A^3+1)/(A^2+1) ?

The answer to 5+A=(A^3+1)/(A^2+1) is A=-1/10+i(sqrt(79))/(10),A=-1/10-i(sqrt(79))/(10)

Solve for A: 5+A=(A^3+1)/(A^2+1)

The solution is A=-1/10+i(sqrt(79))/(10),A=-1/10-i(sqrt(79))/(10)

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5 + A = \frac{A ^{3} + 1}{A ^{2} + 1}

A = - \frac{1}{10} + i \frac{79}{10}, A = - \frac{1}{10} - i \frac{79}{10}

Solution steps

5 + A = \frac{A ^{3} + 1}{A ^{2} + 1}

Multiply both sides by

A^{2} + 1

5 (A^{2} + 1) + A (A^{2} + 1) = A^{3} + 1

Solve

5 (A^{2} + 1) + A (A^{2} + 1) = A^{3} + 1 : A = - \frac{1}{10} + i \frac{79}{10}, A = - \frac{1}{10} - i \frac{79}{10}

A = - \frac{1}{10} + i \frac{79}{10}, A = - \frac{1}{10} - i \frac{79}{10}

r, S = \frac{a _{1}}{1 - r}

\frac{2}{x} + 1 = \frac{4}{x + 2}

\frac{3}{2} = \frac{9}{10 k}

x, x^{- 2} = a

\frac{2 x + 3}{x + 1} = \frac{5}{3}

What is the answer to 5+A=(A^3+1)/(A^2+1) ?
The answer to 5+A=(A^3+1)/(A^2+1) is A=-1/10+i(sqrt(79))/(10),A=-1/10-i(sqrt(79))/(10)
Solve for A: 5+A=(A^3+1)/(A^2+1)
The solution is A=-1/10+i(sqrt(79))/(10),A=-1/10-i(sqrt(79))/(10)