What is the answer to 1/(3x+4)=x-2 ?

The answer to 1/(3x+4)=x-2 is x=(1+2sqrt(7))/3 ,x=(1-2sqrt(7))/3

Solve for x: 1/(3x+4)=x-2

The solution is x=(1+2sqrt(7))/3 ,x=(1-2sqrt(7))/3

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\frac{1}{3 x + 4} = x - 2

x = \frac{1 + 2 7}{3}, x = \frac{1 - 2 7}{3}

Solution steps

\frac{1}{3 x + 4} = x - 2

Multiply both sides by

3 x + 4

1 = x (3 x + 4) - 2 (3 x + 4)

Solve

1 = x (3 x + 4) - 2 (3 x + 4) : x = \frac{1 + 2 7}{3}, x = \frac{1 - 2 7}{3}

x = \frac{1 + 2 7}{3}, x = \frac{1 - 2 7}{3}

Verify Solutions

Find undefined (singularity) points:

x = - \frac{4}{3}

Combine undefined points with solutions:

x = \frac{1 + 2 7}{3}, x = \frac{1 - 2 7}{3}

\frac{- 7}{4 x} + \frac{5}{6 x} = 1

\frac{x ^{2} + 3 x - 4}{x - 3} = 0

\frac{13}{y} = \frac{3}{5}

\frac{2 x}{x + 1} = 8 - \frac{2}{x + 1}

\frac{3}{4} = \frac{75}{x}

What is the answer to 1/(3x+4)=x-2 ?
The answer to 1/(3x+4)=x-2 is x=(1+2sqrt(7))/3 ,x=(1-2sqrt(7))/3
Solve for x: 1/(3x+4)=x-2
The solution is x=(1+2sqrt(7))/3 ,x=(1-2sqrt(7))/3