What is the answer to (x^2+3x-4)/(x-3)=0 ?

The answer to (x^2+3x-4)/(x-3)=0 is x=1,x=-4

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(x^2+3x-4)/(x-3)=0

\frac{x ^{2} + 3 x - 4}{x - 3} = 0

x = 1, x = - 4

Solution steps

\frac{x ^{2} + 3 x - 4}{x - 3} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} + 3 x - 4 = 0

Solve

x^{2} + 3 x - 4 = 0 : x = 1, x = - 4

x = 1, x = - 4

Verify Solutions

Find undefined (singularity) points:

x = 3

Combine undefined points with solutions:

x = 1, x = - 4

\frac{13}{y} = \frac{3}{5}

\frac{2 x}{x + 1} = 8 - \frac{2}{x + 1}

\frac{3}{4} = \frac{75}{x}

5 = \frac{2 x ^{2} - 8 x}{1 - x}

\frac{2 x + 1}{x + 1} = \frac{3}{x + 1}

What is the answer to (x^2+3x-4)/(x-3)=0 ?
The answer to (x^2+3x-4)/(x-3)=0 is x=1,x=-4
Solve for x: (x^2+3x-4)/(x-3)=0
The solution is x=1,x=-4