What is the answer to 1/(x+1)+1/(x+2)=0 ?

The answer to 1/(x+1)+1/(x+2)=0 is x=-3/2

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1/(x+1)+1/(x+2)=0

\frac{1}{x + 1} + \frac{1}{x + 2} = 0

x = - \frac{3}{2}

Solution steps

\frac{1}{x + 1} + \frac{1}{x + 2} = 0

Multiply by LCM

2 x + 3 = 0

Move

3

to the right side

2 x = - 3

Divide both sides by

2

x = - \frac{3}{2}

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = - 2

Combine undefined points with solutions:

x = - \frac{3}{2}

1 = \frac{12 x ^{2}}{x ^{4} + 36}

- \frac{2}{9} = \frac{5}{x}

20 - \frac{7}{x} = 2 x

\frac{12 + 13 x}{4 x} = x

y, y^{- 1} = x

What is the answer to 1/(x+1)+1/(x+2)=0 ?
The answer to 1/(x+1)+1/(x+2)=0 is x=-3/2
Solve for x: 1/(x+1)+1/(x+2)=0
The solution is x=-3/2