What is the answer to 8x-x^{-2}=0 ?

The answer to 8x-x^{-2}=0 is x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i

Solve for x: 8x-x^{-2}=0

The solution is x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i

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8 x - x^{- 2} = 0

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

Solution steps

8 x - x^{- 2} = 0

Refine

8 x - \frac{1}{x ^{2}} = 0

Multiply both sides by

x^{2}

8 x^{3} - 1 = 0

Solve

8 x^{3} - 1 = 0 : x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

12 - \frac{25}{x} = 4 + \frac{7}{x}

\frac{x + 1}{4} = \frac{1}{2 x}

\frac{a + 4}{5 + a} = 1

(\frac{6}{y})^{2} + y^{2} = 13

\frac{1}{x} + 3 = 0

What is the answer to 8x-x^{-2}=0 ?
The answer to 8x-x^{-2}=0 is x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i
Solve for x: 8x-x^{-2}=0
The solution is x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i