What is the answer to (8^{-1})/(4^{-1)}-a^{-1}=1 ?

The answer to (8^{-1})/(4^{-1)}-a^{-1}=1 is a=-2

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(8^{-1})/(4^{-1)}-a^{-1}=1

\frac{8 ^{- 1}}{4 ^{- 1}} - a^{- 1} = 1

a = - 2

Solution steps

\frac{8 ^{- 1}}{4 ^{- 1}} - a^{- 1} = 1

Refine

\frac{1}{2} - \frac{1}{a} = 1

Multiply by LCM

a - 2 = 2 a

Move

2

to the right side

a = 2 a + 2

Move

2 a

to the left side

- a = 2

Divide both sides by

- 1

a = - 2

Verify Solutions

Find undefined (singularity) points:

a = 0

Combine undefined points with solutions:

a = - 2

\frac{( 2 x - 3 ) ( x + 5 )}{x - 7} = 0

\frac{x + 2}{x} = \frac{3}{5}

4 + \frac{6}{x} = \frac{5}{2}

\frac{5}{x} + 3 = \frac{4}{x - 1}

\frac{1}{x} + \frac{3}{x} = 4

What is the answer to (8^{-1})/(4^{-1)}-a^{-1}=1 ?
The answer to (8^{-1})/(4^{-1)}-a^{-1}=1 is a=-2
Solve for a: (8^{-1})/(4^{-1)}-a^{-1}=1
The solution is a=-2