What is the answer to (2x(x-3)+1)/((x+3)(x-1))=0 ?

The answer to (2x(x-3)+1)/((x+3)(x-1))=0 is x=(3+sqrt(7))/2 ,x=(3-sqrt(7))/2

Solve for x: (2x(x-3)+1)/((x+3)(x-1))=0

The solution is x=(3+sqrt(7))/2 ,x=(3-sqrt(7))/2

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\frac{2 x ( x - 3 ) + 1}{( x + 3 ) ( x - 1 )} = 0

x = \frac{3 + 7}{2}, x = \frac{3 - 7}{2}

Solution steps

\frac{2 x ( x - 3 ) + 1}{( x + 3 ) ( x - 1 )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

2 x (x - 3) + 1 = 0

Solve

2 x (x - 3) + 1 = 0 : x = \frac{3 + 7}{2}, x = \frac{3 - 7}{2}

x = \frac{3 + 7}{2}, x = \frac{3 - 7}{2}

Verify Solutions

Find undefined (singularity) points:

x = - 3, x = 1

Combine undefined points with solutions:

x = \frac{3 + 7}{2}, x = \frac{3 - 7}{2}

\frac{x - 3}{x + 2} = \frac{3}{4}

\frac{- 12 x + 20}{( x + 3 ) ( x - 4 )} = 0

\frac{2}{x - 1} - \frac{6}{2 x + 1} = 5

7 - \frac{2}{x} = 4 + \frac{10}{x}

\frac{x}{x + 3} + \frac{5}{x + 4} = 0

What is the answer to (2x(x-3)+1)/((x+3)(x-1))=0 ?
The answer to (2x(x-3)+1)/((x+3)(x-1))=0 is x=(3+sqrt(7))/2 ,x=(3-sqrt(7))/2
Solve for x: (2x(x-3)+1)/((x+3)(x-1))=0
The solution is x=(3+sqrt(7))/2 ,x=(3-sqrt(7))/2