What is the answer to solvefor f,f^{-1}(x)=x ?

The answer to solvefor f,f^{-1}(x)=x is f=1;\quad x\ne 0

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solvefor f,f^{-1}(x)=x

solve for

f, f^{- 1} (x) = x

f = 1; x \neq = 0

Solution steps

f^{- 1} (x) = x

Refine

\frac{x}{f} = x

Multiply both sides by

f

x = x f

Switch sides

x f = x

Divide both sides by

x; x \neq = 0

f = 1; x \neq = 0

Verify Solutions

Find undefined (singularity) points:

f = 0

Combine undefined points with solutions:

f = 1; x \neq = 0

\frac{x + 1}{x - 2} = x - 3

x^{- 3} = 64

\frac{2 x ^{2} + 9 x - 5}{x ^{4} + 1} = 0

\frac{- 5}{x - 5} + \frac{2}{x + 9} = 1

\frac{10}{2} = \frac{100}{r}

What is the answer to solvefor f,f^{-1}(x)=x ?
The answer to solvefor f,f^{-1}(x)=x is f=1;\quad x\ne 0