What is the answer to 2=Q+f/b ?

The answer to 2=Q+f/b is b= f/(2-Q);\quad \ne True for all Q

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2=Q+f/b

2 = Q + \frac{f}{b}

b = \frac{f}{2 - Q}; \neq = True for all Q

Solution steps

2 = Q + \frac{f}{b}

Move

Q

to the left side

2 - Q = \frac{f}{b}

Multiply both sides by

b

2 b - Q b = f

Factor

2 b - Q b : b (2 - Q)

b (2 - Q) = f

Divide both sides by

2 - Q; \neq =

True for all

Q

b = \frac{f}{2 - Q}; \neq = True for all Q

\frac{6}{x} + \frac{x}{2} = 4

\frac{6}{x - 8} = 3 x

- \frac{2}{x} = - \frac{5}{x - 6}

\frac{a}{b} = \frac{c}{d + x}

x^{- 2} - 2 x^{- 1} - 35 = 0

What is the answer to 2=Q+f/b ?
The answer to 2=Q+f/b is b= f/(2-Q);\quad \ne True for all Q