What is the answer to (x^2+3x-10)/(x-2)=x+5 ?

The answer to (x^2+3x-10)/(x-2)=x+5 is x\ne 2

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(x^2+3x-10)/(x-2)=x+5

\frac{x ^{2} + 3 x - 10}{x - 2} = x + 5

x \neq = 2

Solution steps

\frac{x ^{2} + 3 x - 10}{x - 2} = x + 5

Simplify

\frac{x ^{2} + 3 x - 10}{x - 2} : x + 5

x + 5 = x + 5

Both sides are equal

True for all x

Verify Solutions

Find undefined (singularity) points:

x = 2

Since the equation is undefined for:

2

x \neq = 2

g, h = \frac{g - 3}{g - 2}

\frac{x - 7}{x - 4} = \frac{5}{x}

\frac{4 x}{x - 2} + 3 = 1

(12.2)^{2} = \frac{640}{m}

p, p^{- 1} + q^{- 1} = - 2

What is the answer to (x^2+3x-10)/(x-2)=x+5 ?
The answer to (x^2+3x-10)/(x-2)=x+5 is x\ne 2
Solve for x: (x^2+3x-10)/(x-2)=x+5
The solution is x\ne 2