What is the answer to (2x}{x-2}=1+\frac{x+2)/2 ?

The answer to (2x}{x-2}=1+\frac{x+2)/2 is x=4,x=-2

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(2x}{x-2}=1+\frac{x+2)/2

\frac{2 x}{x - 2} = 1 + \frac{x + 2}{2}

x = 4, x = - 2

Solution steps

\frac{2 x}{x - 2} = 1 + \frac{x + 2}{2}

Multiply by LCM

4 x = 2 (x - 2) + (x + 2) (x - 2)

Solve

4 x = 2 (x - 2) + (x + 2) (x - 2) : x = 4, x = - 2

x = 4, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 2

Combine undefined points with solutions:

x = 4, x = - 2

(\frac{2}{x + 1} + 2)^{2} - 5 = 11

\frac{12}{y - 1} = \frac{2}{3}

- \frac{2}{5 x} + \frac{3}{20 x} = 5

\frac{1}{x} + 2 = 0

9 \cdot \frac{1000}{1000 + x} = 2

What is the answer to (2x}{x-2}=1+\frac{x+2)/2 ?
The answer to (2x}{x-2}=1+\frac{x+2)/2 is x=4,x=-2
Solve for x: (2x}{x-2}=1+\frac{x+2)/2
The solution is x=4,x=-2