What is the answer to 1/x =x^2 ?

The answer to 1/x =x^2 is x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i

Solve for x: 1/x =x^2

The solution is x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i

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\frac{1}{x} = x^{2}

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

Solution steps

\frac{1}{x} = x^{2}

Multiply both sides by

x

1 = x^{3}

Solve

1 = x^{3} : x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

\frac{- 30}{x + 2} = \frac{- 20}{x}

2 = \frac{250}{x ^{3}}

\frac{x}{1 - x} = y, x

\frac{1 - 8 x ^{3}}{x ^{2}} = 0

\frac{4 x}{x + 1} = 6 - \frac{4}{x + 1}

What is the answer to 1/x =x^2 ?
The answer to 1/x =x^2 is x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i
Solve for x: 1/x =x^2
The solution is x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i