What is 3(x-2)+2x(x+3)>(2x-1)(x-4) ?

The solution to 3(x-2)+2x(x+3)>(2x-1)(x-4) is x> 5/9

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3(x-2)+2x(x+3)>(2x-1)(x-4)

3 (x - 2) + 2 x (x + 3) > (2 x - 1) (x - 4)

x > \frac{5}{9}

Interval Notation

(\frac{5}{9}, \infty)

Decimal

x > 0.55555 \dots

Solution steps

3 (x - 2) + 2 x (x + 3) > (2 x - 1) (x - 4)

Rewrite in standard form

9 x - 5 > 0

Move

5

to the right side

9 x > 5

Divide both sides by

9

x > \frac{5}{9}

4 a^{2} + 4 ab - 80 b^{2}

\frac{\frac{n}{2}}{2}

\frac{1}{7} \leq \frac{1 - 7 t}{8} < \frac{7}{8}

(x + 1)^{2} = 81

\frac{1}{7} x - 5 = 8

What is 3(x-2)+2x(x+3)>(2x-1)(x-4) ?
The solution to 3(x-2)+2x(x+3)>(2x-1)(x-4) is x> 5/9