What are the solutions to the equation 2x^2=19x+33 ?

The solutions to the equation 2x^2=19x+33 are x=11,x=-3/2

Find the zeros of 2x^2=19x+33

The zeros of 2x^2=19x+33 are x=11,x=-3/2

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2 x^{2} = 19 x + 33

x = 11, x = - \frac{3}{2}

Solution steps

2 x^{2} = 19 x + 33

Move

33

to the left side

2 x^{2} - 33 = 19 x

Move

19 x

to the left side

2 x^{2} - 33 - 19 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 19 x - 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 2 ( - 33 )}{2 \cdot 2}

(- 19)^{2} - 4 \cdot 2 (- 33) = 25

x_{1, 2} = \frac{- ( - 19 ) \pm 25}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 25}{2 \cdot 2}, x_{2} = \frac{- ( - 19 ) - 25}{2 \cdot 2}

x = \frac{- ( - 19 ) + 25}{2 \cdot 2} : 11

x = \frac{- ( - 19 ) - 25}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 11, x = - \frac{3}{2}

- \frac{4}{7} x = - 1

(310)^{2}

\frac{2}{5 x} + 6 < \frac{3}{5} - 2 x

p + \frac{p ^{2} + p + q - 5}{- p + 3}

What are the solutions to the equation 2x^2=19x+33 ?
The solutions to the equation 2x^2=19x+33 are x=11,x=-3/2
Find the zeros of 2x^2=19x+33
The zeros of 2x^2=19x+33 are x=11,x=-3/2