What is 2/(5x)+6< 3/5-2x ?

The solution to 2/(5x)+6< 3/5-2x is x<(-27-sqrt(649))/(20)\lor (sqrt(649)-27)/(20)<x<0

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2/(5x)+6< 3/5-2x

\frac{2}{5 x} + 6 < \frac{3}{5} - 2 x

x < \frac{- 27 - 649}{20} or \frac{649 - 27}{20} < x < 0

Solution steps

\frac{2}{5 x} + 6 < \frac{3}{5} - 2 x

Rewrite in standard form

\frac{10 x ^{2} + 27 x + 2}{x} < 0

Factor

10 x^{2} + 27 x + 2 : (x - \frac{- 27 + 649}{20}) (x - \frac{- 27 - 649}{20})

\frac{( x - \frac{- 27 + 649}{20} ) ( x - \frac{- 27 - 649}{20} )}{x} < 0

Identify the intervals

x < \frac{- 27 - 649}{20} or \frac{649 - 27}{20} < x < 0

p + \frac{p ^{2} + p + q - 5}{- p + 3}

25 y^{2} - 81 = 0

5 \geq \frac{1}{5} (- 10) - 5

(x - 6)^{2} = 20 - 2 x

(\frac{a}{b ^{3}})^{4}

What is 2/(5x)+6< 3/5-2x ?
The solution to 2/(5x)+6< 3/5-2x is x<(-27-sqrt(649))/(20)\lor (sqrt(649)-27)/(20)<x<0