What is the answer to 2/(3c-2)=2+c ?

The answer to 2/(3c-2)=2+c is c=(-2+sqrt(22))/3 ,c=-(2+sqrt(22))/3

Solve for c: 2/(3c-2)=2+c

The solution is c=(-2+sqrt(22))/3 ,c=-(2+sqrt(22))/3

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\frac{2}{3 c - 2} = 2 + c

c = \frac{- 2 + 22}{3}, c = - \frac{2 + 22}{3}

Decimal Notation

c = 0.89680 \dots, c = - 2.23013 \dots

Solution steps

\frac{2}{3 c - 2} = 2 + c

Multiply both sides by

3 c - 2

2 = 2 (3 c - 2) + c (3 c - 2)

Solve

2 = 2 (3 c - 2) + c (3 c - 2) : c = \frac{- 2 + 22}{3}, c = - \frac{2 + 22}{3}

c = \frac{- 2 + 22}{3}, c = - \frac{2 + 22}{3}

Verify Solutions

Find undefined (singularity) points:

c = \frac{2}{3}

Combine undefined points with solutions:

c = \frac{- 2 + 22}{3}, c = - \frac{2 + 22}{3}

\frac{z + ( 10 )}{( z )} = 6

\frac{x}{12} = \frac{4}{x}

d, m = \frac{g}{d} + 3

\frac{x - 6}{x - 4} = \frac{- 5}{x}

\frac{( n + 2 ) !}{( n - 1 ) !} = 30 n

What is the answer to 2/(3c-2)=2+c ?
The answer to 2/(3c-2)=2+c is c=(-2+sqrt(22))/3 ,c=-(2+sqrt(22))/3
Solve for c: 2/(3c-2)=2+c
The solution is c=(-2+sqrt(22))/3 ,c=-(2+sqrt(22))/3