What is the answer to ((n+2)!)/((n-1)!)=30n ?

The answer to ((n+2)!)/((n-1)!)=30n is n=0,n=4,n=-7

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((n+2)!)/((n-1)!)=30n

\frac{( n + 2 ) !}{( n - 1 ) !} = 30 n

n = 0, n = 4, n = - 7

Solution steps

\frac{( n + 2 ) !}{( n - 1 ) !} = 30 n

Simplify

\frac{( n + 2 ) !}{( n - 1 ) !} : n (n + 2) (n + 1)

n (n + 2) (n + 1) = 30 n

Solve

n (n + 2) (n + 1) = 30 n : n = 0, n = 4, n = - 7

n = 0, n = 4, n = - 7

\frac{( 2 x + 1 ) ( x - 1 )}{( x + 1 )} = 0

\frac{6}{12} = \frac{2}{n}

a, hb + 5 = \frac{- b}{2 a}

2 x - 4 x^{- 1} = 7

x^{2} + \frac{5}{x ^{2}} = 6

What is the answer to ((n+2)!)/((n-1)!)=30n ?
The answer to ((n+2)!)/((n-1)!)=30n is n=0,n=4,n=-7
Solve for n: ((n+2)!)/((n-1)!)=30n
The solution is n=0,n=4,n=-7