What is (4a^2-36a)/(2a^4-24a^3+54a^2) ?

The solution to (4a^2-36a)/(2a^4-24a^3+54a^2) is 2/(a(a-3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (4a^2-36a)/(2a^4-24a^3+54a^2)

simplify

\frac{4 a ^{2} - 36 a}{2 a ^{4} - 24 a ^{3} + 54 a ^{2}}

\frac{2}{a ( a - 3 )}

Solution steps

\frac{4 a ^{2} - 36 a}{2 a ^{4} - 24 a ^{3} + 54 a ^{2}}

Factor

4 a^{2} - 36 a : 4 a (a - 9)

= \frac{4 a ( a - 9 )}{2 a ^{4} - 24 a ^{3} + 54 a ^{2}}

Factor

2 a^{4} - 24 a^{3} + 54 a^{2} : 2 a^{2} (a - 3) (a - 9)

= \frac{4 a ( a - 9 )}{2 a ^{2} ( a - 3 ) ( a - 9 )}

Cancel the common factor:

a - 9

= \frac{4 a}{2 a ^{2} ( a - 3 )}

Factor the number:

4 = 2 \cdot 2

= \frac{2 \cdot 2 a}{2 a ^{2} ( a - 3 )}

Cancel the common factor:

2

= \frac{2 a}{a ^{2} ( a - 3 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

a^{2} = aa

= \frac{2 a}{aa ( a - 3 )}

Cancel the common factor:

a

= \frac{2}{a ( a - 3 )}

\frac{26}{6} - \frac{4}{3}

3 x^{2} + 3 x + 9 = 0

- \frac{3}{2} + \frac{1}{2}

- \frac{1}{3} + 3

j + 7 = 5

What is (4a^2-36a)/(2a^4-24a^3+54a^2) ?
The solution to (4a^2-36a)/(2a^4-24a^3+54a^2) is 2/(a(a-3))