What are the solutions to the equation 3x^2+3x+9=0 ?

The solutions to the equation 3x^2+3x+9=0 are x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2

Find the zeros of 3x^2+3x+9=0

The zeros of 3x^2+3x+9=0 are x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2

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3 x^{2} + 3 x + 9 = 0

x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

Solution steps

3 x^{2} + 3 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

Simplify

3^{2} - 4 \cdot 3 \cdot 9 : 311 i

x_{1, 2} = \frac{- 3 \pm 3 11 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 3 11 i}{2 \cdot 3}, x_{2} = \frac{- 3 - 3 11 i}{2 \cdot 3}

x = \frac{- 3 + 3 11 i}{2 \cdot 3} : - \frac{1}{2} + i \frac{11}{2}

x = \frac{- 3 - 3 11 i}{2 \cdot 3} : - \frac{1}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

- \frac{3}{2} + \frac{1}{2}

- \frac{1}{3} + 3

j + 7 = 5

\frac{x}{2} + \frac{3}{4} = 1

\frac{1}{4} y^{2} + y + 1 = 1

What are the solutions to the equation 3x^2+3x+9=0 ?
The solutions to the equation 3x^2+3x+9=0 are x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2
Find the zeros of 3x^2+3x+9=0
The zeros of 3x^2+3x+9=0 are x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2