What are the solutions to the equation x^2+3x+1=0 ?

The solutions to the equation x^2+3x+1=0 are x=(-3+sqrt(5))/2 ,x=(-3-sqrt(5))/2

Find the zeros of x^2+3x+1=0

The zeros of x^2+3x+1=0 are x=(-3+sqrt(5))/2 ,x=(-3-sqrt(5))/2

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x^{2} + 3 x + 1 = 0

x = \frac{- 3 + 5}{2}, x = \frac{- 3 - 5}{2}

Solution steps

x^{2} + 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 1 = 5

x_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 5}{2 \cdot 1}, x_{2} = \frac{- 3 - 5}{2 \cdot 1}

x = \frac{- 3 + 5}{2 \cdot 1} : \frac{- 3 + 5}{2}

x = \frac{- 3 - 5}{2 \cdot 1} : \frac{- 3 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 5}{2}, x = \frac{- 3 - 5}{2}

\frac{- 4}{5 ^{2}}

4 a^{2} - 20 a + 25

7 + 7 x \geq - 14

\frac{4}{3} - \frac{7}{9}

x^{2} - 8 x + 18 = 0

What are the solutions to the equation x^2+3x+1=0 ?
The solutions to the equation x^2+3x+1=0 are x=(-3+sqrt(5))/2 ,x=(-3-sqrt(5))/2
Find the zeros of x^2+3x+1=0
The zeros of x^2+3x+1=0 are x=(-3+sqrt(5))/2 ,x=(-3-sqrt(5))/2