What are the solutions to the equation (7x+12)^2=27 ?

The solutions to the equation (7x+12)^2=27 are x=(3sqrt(3)-12)/7 ,x=(-3sqrt(3)-12)/7

Find the zeros of (7x+12)^2=27

The zeros of (7x+12)^2=27 are x=(3sqrt(3)-12)/7 ,x=(-3sqrt(3)-12)/7

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(7 x + 12)^{2} = 27

x = \frac{3 3 - 12}{7}, x = \frac{- 3 3 - 12}{7}

Solution steps

(7 x + 12)^{2} = 27

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

7 x + 12 = 27 : x = \frac{3 3 - 12}{7}

Solve

7 x + 12 = - 27 : x = \frac{- 3 3 - 12}{7}

The solutions to the quadratic equation are:

x = \frac{3 3 - 12}{7}, x = \frac{- 3 3 - 12}{7}

25 - 9

a^{4}

- 0.25 x - 6 \leq - 3

- 24 x^{3} + 72 x

\frac{x ^{2}}{2} + \frac{3}{2} x = 6

What are the solutions to the equation (7x+12)^2=27 ?
The solutions to the equation (7x+12)^2=27 are x=(3sqrt(3)-12)/7 ,x=(-3sqrt(3)-12)/7
Find the zeros of (7x+12)^2=27
The zeros of (7x+12)^2=27 are x=(3sqrt(3)-12)/7 ,x=(-3sqrt(3)-12)/7