What are the solutions to the equation (x^2)/2+3/2 x=6 ?

The solutions to the equation (x^2)/2+3/2 x=6 are x=(-3+sqrt(57))/2 ,x=(-3-sqrt(57))/2

Find the zeros of (x^2)/2+3/2 x=6

The zeros of (x^2)/2+3/2 x=6 are x=(-3+sqrt(57))/2 ,x=(-3-sqrt(57))/2

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\frac{x ^{2}}{2} + \frac{3}{2} x = 6

x = \frac{- 3 + 57}{2}, x = \frac{- 3 - 57}{2}

Solution steps

\frac{x ^{2}}{2} + \frac{3}{2} x = 6

Multiply both sides by

2

x^{2} + 3 x = 12

Move

12

to the left side

x^{2} + 3 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 12) = 57

x_{1, 2} = \frac{- 3 \pm 57}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 57}{2 \cdot 1}, x_{2} = \frac{- 3 - 57}{2 \cdot 1}

x = \frac{- 3 + 57}{2 \cdot 1} : \frac{- 3 + 57}{2}

x = \frac{- 3 - 57}{2 \cdot 1} : \frac{- 3 - 57}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 57}{2}, x = \frac{- 3 - 57}{2}

- 4 (x + 1) + 6 x = 2 (x + 2) - 8

(- 81)^{\frac{3}{4}}

6 k^{2} - 3 k - 84

- \frac{21}{- 7}

\frac{x}{2} + x = 3

What are the solutions to the equation (x^2)/2+3/2 x=6 ?
The solutions to the equation (x^2)/2+3/2 x=6 are x=(-3+sqrt(57))/2 ,x=(-3-sqrt(57))/2
Find the zeros of (x^2)/2+3/2 x=6
The zeros of (x^2)/2+3/2 x=6 are x=(-3+sqrt(57))/2 ,x=(-3-sqrt(57))/2