What are the solutions to the equation 5x^2+6x-2=0 ?

The solutions to the equation 5x^2+6x-2=0 are x=(-3+sqrt(19))/5 ,x=-(3+sqrt(19))/5

Find the zeros of 5x^2+6x-2=0

The zeros of 5x^2+6x-2=0 are x=(-3+sqrt(19))/5 ,x=-(3+sqrt(19))/5

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5 x^{2} + 6 x - 2 = 0

x = \frac{- 3 + 19}{5}, x = - \frac{3 + 19}{5}

Solution steps

5 x^{2} + 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

6^{2} - 4 \cdot 5 (- 2) = 219

x_{1, 2} = \frac{- 6 \pm 2 19}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 6 + 2 19}{2 \cdot 5}, x_{2} = \frac{- 6 - 2 19}{2 \cdot 5}

x = \frac{- 6 + 2 19}{2 \cdot 5} : \frac{- 3 + 19}{5}

x = \frac{- 6 - 2 19}{2 \cdot 5} : - \frac{3 + 19}{5}

The solutions to the quadratic equation are:

x = \frac{- 3 + 19}{5}, x = - \frac{3 + 19}{5}

5 (2 + 42)

- 4 < 2 (x - 3) \leq 4

5 (x + 2) = 3 (2 x - 3)

- 5 n + 6 \geq - 7 (5 n - 6) - 6 n

x^{2} - 42 = - x

What are the solutions to the equation 5x^2+6x-2=0 ?
The solutions to the equation 5x^2+6x-2=0 are x=(-3+sqrt(19))/5 ,x=-(3+sqrt(19))/5
Find the zeros of 5x^2+6x-2=0
The zeros of 5x^2+6x-2=0 are x=(-3+sqrt(19))/5 ,x=-(3+sqrt(19))/5