What is the answer to 6x^{-2}+x^{-1}=1 ?

The answer to 6x^{-2}+x^{-1}=1 is x=3,x=-2

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6x^{-2}+x^{-1}=1

6 x^{- 2} + x^{- 1} = 1

x = 3, x = - 2

Solution steps

6 x^{- 2} + x^{- 1} = 1

Refine

\frac{6}{x ^{2}} + \frac{1}{x} = 1

Multiply by LCM

6 + x = x^{2}

Solve

6 + x = x^{2} : x = 3, x = - 2

x = 3, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 3, x = - 2

\frac{( x - 3 ) ^{2}}{x ^{2} - 5 x} = 1

\frac{x}{x - 2} + \frac{4}{x - 2} = 10

y, x = \frac{1}{y - 2}

\frac{x - 7}{3 x} + 1 = \frac{x + 5}{x}

\frac{45}{30} = \frac{36}{x}

What is the answer to 6x^{-2}+x^{-1}=1 ?
The answer to 6x^{-2}+x^{-1}=1 is x=3,x=-2
Solve for x: 6x^{-2}+x^{-1}=1
The solution is x=3,x=-2