What are the solutions to the equation 34x+78=x^2+34x-43 ?

The solutions to the equation 34x+78=x^2+34x-43 are x=11,x=-11

Find the zeros of 34x+78=x^2+34x-43

The zeros of 34x+78=x^2+34x-43 are x=11,x=-11

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34 x + 78 = x^{2} + 34 x - 43

x = 11, x = - 11

Solution steps

34 x + 78 = x^{2} + 34 x - 43

Switch sides

x^{2} + 34 x - 43 = 34 x + 78

Move

43

to the right side

x^{2} + 34 x = 34 x + 121

Move

34 x

to the left side

x^{2} = 121

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 121, x = - 121

121 = 11

- 121 = - 11

x = 11, x = - 11

(\frac{x ^{\frac{1}{5}} y ^{\frac{6}{5}}}{z ^{\frac{2}{5}}})^{5}

x^{2} (21 - 20 x) \leq 1

y^{2} - 3 y + 2 = 0

(x - 2)^{2} = 1

- 6 = \frac{x}{8} + 4

What are the solutions to the equation 34x+78=x^2+34x-43 ?
The solutions to the equation 34x+78=x^2+34x-43 are x=11,x=-11
Find the zeros of 34x+78=x^2+34x-43
The zeros of 34x+78=x^2+34x-43 are x=11,x=-11